Well, I don't know. I looked for a stock who's symbol was N and that had a rate of return of two-tenths-of-one-percent. I couldn't find that either.
Here's what your lab has to say:
http://extension.msstate.edu/agriculture/crops/soils/nitrogen-fertility
"Small quantities of soil N are provided by residue from plants that do not fix atmospheric N. Organic matter in Mississippi soils typically ranges from 0.5 to 2.0 percent by weight of the upper six inches. Typically organic matter is approximately 5 percent N, so total N in the topsoil ranges from 500 lb/acre to 2000 lb/acre. However, only a very small portion of the total N is available to plants within a growing season. Organic matter is replenished by returning crop residues to the soil or introducing other organic sources such as manures or animal bedding."
Let's work through that. For ease let's assume your OM content was 2%. For rough calculation, the top six inches of soil weighs 2-million pounds. If 2% of that is OM, then you have 40,000 lbs of it - organic matter. Relying on the information above, then, 5% of the 40,000 lbs is N or 2,000 pounds in a million. Divide 2,000 by one million and you get back to 0.20%. See how I conveniently worked back to the answer you wanted? Just lose a million pounds of soil. I don't get it.....
My guess is the 0.2% is the percentage of potential N derived from OM in the soil plow layer, not all of which is available. How that's helpful I do not know.
At the end of the day I would pretend I didn't see that N number.